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The original equation is x^3y+y-3=x-2xy^2 2 1-242 3x7 Y' = it xstyxy b. The equations of the two lines tangent to the given curve at

The original equation is x^3y+y-3=x-2xy^2

2 1-242 3x7 Y' = it xstyxy b. The equations of the two lines tangent to the given curve at x = 1

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