The overhead reach distances of adult females are normally distributed with a mean of 204 cm and a standard deviation of 8.5 cm. a. Find the probability that an individual distance is greater than 216 cm. I). Find the probability that the mean for 23 randomly selected distances is greater than 202 cm. 0. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? First, convert the distance to the corresponding 2 score using 2 = and the population distribution statistics, where x is the given value, p is the mean, and 6 is the standard deviation. Calculate z, rounding to two decimal places. 216-204 8.5 1.41 The probability is the area to the right ofz = 1.41 under the standard normal distribution curve, which is shaded in the graph to the right. ,0}? E z=1.41 First nd the area to the left of z = 1.41, rounding to four decimal places. The area to the left is 0.9207. Subtract this value from 1 to nd the area to the right. 1 - 0.9207 = 0.0793 Calculator Print @ ... _.._...._I_ n_:..._-.._ I._I