Question
The point P(-1,-2) is on the graph of y=0.2x^3+1.8x^2+3.6x. Let Q be the point with the coordinates (x,0.2x^3+1.8x^2+3.6x). (a). Find a formula for the slope
The point P(-1,-2) is on the graph of y=0.2x^3+1.8x^2+3.6x. Let Q be the point with the coordinates (x,0.2x^3+1.8x^2+3.6x).
(a). Find a formula for the slope of the secant line PQ in term of x
(b) Find the slope of the secant line PQ for the given values of x. -0.9,-0.99,-1.01,-1.1
(c) What number would you use as an estimate for the slope of the tangent line at P(-1,-2)
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Differential Equations
Authors: Paul Blanchard, Paul S Boyer, Robert L Devaney, Glen R Hall
4th Edition
1133388086, 9781133388081
