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The point (Xo, 1'0) = 0 lies on the curvexl ' 2 5 .re y =21 e Show that (1'1, _1-'1} = (CI, 4} lies

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The point (Xo, 1'0) = 0 lies on the curvexl ' 2 5 .re" y =21 e Show that (1'1, _1-'1} = (CI, 4} lies on the tangent to the curve at (In, yo}

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