Question
The Pourbaix diagram for the Zn-H 2 O system is shown below: (i) By using this Pourbaix diagram below experimentally determined that the equation of
The Pourbaix diagram for the Zn-H2O system is shown below:
(i) By using this Pourbaix diagram below experimentally determined that the equation of the (a) line which represents the equilibrium between Zn and Zn(OH)2 is at pH 8.48, considering that the value of the concentration of Zn2+ used is 10-6 molar/litre and Go for the reaction of Zn2+ + 2H2O Zn(OH)2 + 2H+ is 62501 Jmole-.
(ii) By using this Pourbaix diagram experimentally determined that the equation of the (b) line which represents the equilibrium between Zn(OH)2 and HZnO2- is at pH 10.7, considering that the value of the concentration of Zn2+ used is 10-6 molar/litre and Go for the reaction of Zn(OH)2 H+ + HZnO2- is 95085 Jmole-.
(iii) To operate in passivity conditions when using Zn metal, the pH of the system must be between 8.48 and 10.7. Support the validity of this statement in aerated and de-aerated solutions environments, respectively.
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