The probability values were found to be f(0) = 0.2466, f(1) = 0.3452, and f(2) = 0.2417. We also determined that the probability of having 3 or more breakdowns in a day can be found using the expression 1 (f(0) + f(1) + f(2)). Substitute these values to find the probability of 3 or more breakdowns in one day, rounding the result to four decimal places