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The problem. = (100) 5 (m1-mz). (1.6) Note that the magnitude scale is defined in such a fashion that a fainter object has a higher

The problem.

= (100) 5 (m1-mz). (1.6) Note that the magnitude scale is defined in such a fashion that a fainter object has a higher value of magnitude. On taking the logarithm of (1.6), we find M1 - my = 2.5log10 (1.7)

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