The purple colored solution formed when cobalt(II) chloride is dissolved in hydrochloric acid is an example of a chemical equilibrium represented by the reaction below: Co(H2O)62+ (aq) + 4CI (aq) = [CoCl 4] (aq) + 6H2O (l) Image: Royal Society of Chemistry At room temperature, the reaction system is purple When the system has a greater concentration of COC142, the reaction mixture turns more blue. When the system has a greater concentration of Co(H2O)62+, the reaction mixture turns more pink. Predict what will happen when NaCl is added to the solution at equilibrium described above. Look at the balanced equation of the equilibrium mixture: Co(H2O)62+(aq) + 4CI (aq) = [CoCl4] (aq) + 6H2O (l) What happens upon the addition of NaCl (aq)? Hint: NaCl (aq) consists of Na* (aq) and Cl(aq) ions. This effectively adds Cl(aq) ions to the solution. There will be choose your answer... so the instantaneous value of Q compared to K will be This means that the position of equilibrium will have to choose your answer... choose your answer... to re-establish equilibrium,