The purpose of this assignment is to write C++ code that does the following: IOStream operator < < and operator >> overloads to read and
The purpose of this assignment is to write C++ code that does the following:
- IOStream operator << and operator >> overloads to read and write employee structs,
- IOStream operator << overload to write a vector
sequence container in a specific format, - read in from cin all employees (until an end-of-file or an error) into a vector using the push_back() call,
- create a copy of all employees read in, stable_sort() such by employee name, and then discard the copy,
- stable_sort() all employees (original variable) by their salary amounts, and,
- give a 2% pay raise to all employees making between $20,000 and $30,000 a year.
- lines starting with #error,
- You need to write code where these lines appear.
- Remember to delete the #error lines before submitting your assignment!
- preceding each #error line are instructions written as comments,
- Write the code as specified with the instructions.
- Refer to the textbooks, course slides, and/or cppreference.com as needed or as appropriate.
- Each employee "record" input will always appear in this order:
- possible whitespace,
- a valid unsigned value for id,
- whitespace,
- a single "word" name string
- i.e., there will be no whitespace will be in the name to make it very easy to read in the string
- whitespace,
- a valid double value for salary
- That said, if the above is incorrect, the stream will encounter an error and the program will abort.
Sample Code With Comments
// add needed #include files here
#error write code here
using namespace std;
struct employee
{
unsigned id;
string name;
double salary;
};
istream& operator >>(istream& is, employee& e)
{
// write code to read in an employee, i.e.,
// e.id followed by e.name followed by e.salary.
#error write code here
return is;
}
ostream& operator <<(ostream& os, employee const& e)
{
// write code to output an employee, i.e.,
// e.id followed by a ' ', followed by
// e.name followed by a ' ', followed by
// e.salary.
#error write code here
return os;
}
//---
ostream& operator <<(ostream& os, vector
{
// write code to output v with each employee here as follows:
// '(', followed by e.id, followed by ',',
// followed by e.name, followed by ',',
// followed by e.salary, followed by ')'.
// with no space(s) before or after such.
#error write code here
return os;
}
//---
int main()
{
vector
// read in all employees from cin (until end-of-file or an error)
// * using a for or while loop
// * with a 1-line for/while loop body calling:
// employees.push_back( /* employee record variable */) to
// to add each employee record.
// APPROX # of lines of code: 3 (with "while" loop); 2 (with "for" loop)
// abort if we did not reach the end-of-file, i.e., an error occurred...
if (!cin.eof())
{
cerr << "ERROR: Invalid input. Aborting." << endl;
return 1;
}
// output the employee records read in...
cout << " RAW_DATA: " << employees << endl;
// create a local scope for some short-lived variables...
{
// make a copy of employees (in another variable)...
// HINT 1: The variable type is still vector
// HINT 2: Choose the variable name you want to use.
// I will use the name "employees_copy" in subsequent
// comments to refer to this variable.
// HINT 3: Pass the employees variable to the copy constructor.
// HINT 4: This is a single-line of code, i.e., a variable declaration
// invoking the copy constructor.
#error write code here
// In
// see Josuttis text, Section 11.9 Sorting Algorithms
// Call stable_sort as follows:
// ARG 1: the "begin" iterator of employees_copy
// ARG 2: the "end" iterator of employees_copy
// ARG 3: pass a less than predicate function/lambda/function object
// that defines less than on two employee records, e1 and e2,
// as follows:
//
// e1.name < e2.name
//
// NOTE 1: Writing a lambda is easiest.
// NOTE 2: The less than function's arguments' type should be
// employee const&.
#error write code here
// output data...
cout << " BY_NAME: " << employees_copy << endl;
}
// the local scope created earlier by { ends with }
// e.g., employees_copy is now destroyed.
// stable_sort employees by salary...
// ARG 1: the "begin" iterator of employees
// ARG 2: the "end" iterator of employees
// ARG 3: a predicate function/lambda/function object that defines
// the less than of two employees as: e1.salary < e2.salary
#error write code here
// output data...
cout << " BY_SALARY: " << employees << endl;
// The boss wants to give a 2% pay raise to employees whose salary is
// between $20,000 and $30,000! Follow the instructions in the comments
// below to do this...
// In
// twice storing the results in two variables: low_end and upper_end:
//
// * low_end: the first find_if() will determine the FIRST iterator
// position where e.salary >= 20000.0 && e.salary <= 30000.0 is true,
// OR, the end iterator position if there was no match, and,
// NOTE: The first find_if() call must start from the "beginning"
// iterator!
//
// * upper_end: the second call will determine the ONE-PAST-THE-LAST
// iterator position where e.salary >= 20000.0 && e.salary <= 30000.0
// is true, OR, the end iterator position if there was no match.
// NOTE: The second find_if() call must start from the low_end
// iterator!
//
// HINTS:
// * Do this as TWO variable declarations.
// * Each variable declaration can either be:
// auto low_end = /* find_if() code */;
// auto upper_end = /* find_if() code */;
// OR:
// vector
// vector
// but, clearly, auto is much simpler.
// * Read more about find_if() in the Josuttis text and/or
// cppreference.com.
#error write code here
// Now that you have the half-open range [low_end,upper_end)
// you can increase all employees' salaries in that range!
// In exactly two lines of code, write a for loop as follows:
// FOR "INIT" CLAUSE: Use auto to declare a variable i whose
// initial value is low_end.
// FOR "TEST" CLAUSE: Keep looping while i != upper_end.
// FOR "INCREMENT" CLAUSE: Write ++i.
// NOTE: DON'T WRITE i++!!
// FOR LOOP BODY: Since the iterator i points to an employee,
// you can access an employee struct's salary member
// with i->salary. Thus, in a single line of code, use the *=
// operator to increase the employee's salary by 2%.
#error write code here
// output data...
cout << "SALARY_ADJUST: " << employees << endl;
// Finally, know you can use
// "beginning" and "end" iterators are not the container's
// beginning and end iterators!
//
// Since you already have [low_end,upper_end), write the
// single line of code to REVERSE all container data in the
// range [low_end,upper_end) by calling
// reverse() function.
//
// See the Josuttis text and/or cppreference.com for the
// definition of reverse. (Use the two argument version.)
#error write code here
// output data...
cout << "AFTER_REVERSE: " << employees << endl;
}
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