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The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is

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The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by Q(t) = t3- 2t2 + 4t + 5. [The unit of current is an ampere 1 A = 1 C/s.] (a) Find the current (in A) when t = 0.7 s. (b) Find the current (in A) when t = 1 s. A At what time (in s) is the current the lowest? t = Need Help? Read It Watch It

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