The reaction between HCI and NaOH is represented below. When equal volumes of 1.00 M NaOH and 1.00 M HCI are mixed, 57.1 kJ of heat is released. What would AH be if 2.00 M HCI and 2.00 M NaOH is used instead of 1.00 M? HCl(aq) + NaOH(aq)- NaCl(aq) + H2O(l) =-57.1 kJ/mol