The reaction of $10\mathrm{.}0g{O}_2(g)$ and excess $H_2(g)$ yields $8\mathrm{.}43g{H}_{2}O(g).$ What is the percent yield of this reaction? First step, write a balanced equation. A$.74\mathrm{.}9\%$ B$.42\mathrm{.}2\%$ C$.27\mathrm{.}3\%$ D$.9\mathrm{.}43\%$ E$.66\mathrm{.}8\%$ The reaction of $10\mathrm{.}0g{O}_2(g)$ and excess $H_2(g)$ yields $8\mathrm{.}43g{H}_{2}O(g).$ What is the percent yield of this reaction? First step, write a balanced equation. A$.74\mathrm{.}9\%$ B$.42\mathrm{.}2\%$ C$.27\mathrm{.}3\%$ D$.$