The reported molar mass for the copper oxide formed in Experiment 1 is 79.55 g/mol. What is the molecular formula of the oxide formed in Experiment 1? Show your calculations. This is the data from experiment 1 a) 47.518g b) 47.518-45.000g = 2.518 c) Mol of O = 2.518 x (1 mol o/ 15.999g o) = 1.5738 x10A-3 mol O Mass of Copper = 45.000g - 35.000 = 10.000 g Cu %3D Moles of Cu 10.000g Cu x (1 mol Cu / 63.546 g Cu) = 1.5736 x 10A-3 mol Cu 1.5738x10A-3 mol 0/1.5736 x 10A-3 = .9998 mol O = 1 mol O 1.5736 x 10A-3 mol Cu/ 1.5736 x 10^-3 = 1 mol Cu 2CU + 02 = 2Cuo