The rest of the questions 1)The mean of the sampling distribution is ( rounded 2 decimal places)2) th standard dviation of the sampling distribution is? ( rounded 2 decimal placesA) th means are equal but the standard deviation of the sampling is similar B) th means and standards deviation are equalC) th means are not equal and the standard deviation of the sampling distribution is largerD) th means are equal but the standard deviation of the sampling distribution is larger C) th means are not equal and the standard deviation of the sampling distribution is smaller That's was the rest of the questions thanks24

For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population. The scores of three students in a study group on a test are 90, 91, 94. Use a sample size of 3. The mean of the population is (Round to two decimal places as needed.) The standard deviation of the population is (Round to two decimal places as needed.) Identify all samples of size 3 with the correct-accompanying means below. A. 94,90,90 x = 91.33 B. 91,91,90 x = 90.67 C. 91,90,94 x = 91.67 D. 94,94,91 x = 93 E. 91,94,91 x = 92 F. 91,90,91 x = 90.67 G. 90,94,91 x = 91.67 H. 90,94,90 x =91.33 L 90,94,94 x = 92.67 J. 90,90,90 x = 90 OK. 94,94,90 x =92.67 L. 90,90,94 x = 91.33 M. 90,91,81 x = 90.67 N. 90,91,90 x = 90.33 0. 90,91,94 x = 91.67 P. 94,81,94 x = 93 Q. 94,90,94 x = 92.67 R. 91,94,90 x =91.67 S. 90,90,91 x = 90.33 T. 91,94,94 x= 93 U. 91,90,90 x = 90.33 V. 94,91,90 x = 91.67 OW. 91,91,91 x = 91 X. 91,91,94 x=92 17Y. 94.91.81 x = 92 172 94.90.91 x=91.67 MT. 94.94.94 %=94 Click to select your answer(s) MacBook Pro