The reversible gas-phase elementary reaction is carried out in an isothermal CSTR with no pressure drop. The feed enters at a volumetric flow rate of v0=5000hourdm3. The feed consists of half ethyl benzene (i.e., A) and half inerts on a molar basis and is well mixed before it enters the reactor (I). The pressure in the reactor is 6atm (so PA0=3atm and P10=3atm, making the entering concentration of ethyl benzene, A,CA0=0.04dm3mol ). The molar flow rate of A is FA0=200hrmol. At the reaction temperature of 640C, the rate constant, kA, is 5.92dm3hratmmol. The equilibrium constant, KP is 9atm and the corresponding equilibrium conversion is Xe=0.84. Reference: Won Jae Lee and Gilbert F. Froment. Ind. Eng. Chem. Res. 2008, 47, pp. 9183-9194. (a) Write out each step of the algorithm. (b) Write the rate of reaction, rA, solely as a function of PA0X,KP and k. (c) Calculate the reactor volume necessary to achieve 90% of the equilibrium conversion, Xe. (d) How would the conversion from part (a) be affected if the reactor diameter increased and height decreased but total volume remained the same? Explain