Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

The sample data support the assertion that there is a different proportion of only children in the G&T program. There is not sufficient sample evidence

image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed
image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed
The sample data support the assertion that there is a different proportion of only children in the G&T program. There is not sufficient sample evidence to support the assertion that there is a different proportion of only children in the G&T program Question Help: 8 Message instructor 0 Question 9 E 0/1 pt '0 3 3 99 In a certain school district, it was observed that 30% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 102 out of 289 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the a = 0.02 level of significance. What is the hypothesized population proportion for this test? p = (Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol . ) Based on the statement of this problem, how many tails would this hypothesis test have? one-tailed test two-tailed test Choose the correct pair of hypotheses for this situation: (D) (E) (F) (A) (B) (C) (D) (E) (F) Using the normal approximation for the binomial distribution (without the continuity correction), was is the test statistic for this sample based on the sample proportion? Z= (Report answer as a decimal accurate to 3 decimal places.) You are now ready to calculate the P-value for this sample. P-value = (Report ammo! accurate to 4 decimal places.) This P-value (and test statistic) leads to a decision to... reject the null accept the null fail to reject the null reject the alternative As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program. There is not sufficient evidence to warrant rejection of the assertion that there is a different proportion of onlychildren in the G&T program. The sample data support the assertion that there is a different proportion of only children in the G&T program. There is not sufficient sample evidence to support the assertion that there is a different proportion of only children in the GEtT program. 4 Question Help: 8 Message instructor . Question 10 80/1 pt '03 399 In a certain school district, it was observed that 35% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 151 out of 376 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the a = 0.02 level of significance. What is the hypothesized population proportion for this test? p = (Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.) Based on the statement of this problem, how many tails would this hypothesis test have? one-tai led test 'two-tailed test Choose the correct pair of hypot'leses for this situation: (D) (Ell (F)| (A) 15) (C) (D) (E) _(F) Using the normal approximation for the binomial distribution (without the continuity correction), was is the test statistic for this sample based on the sample proportion? Z= (Report answer as a decimal accurate to 3 decimal places.) You are now ready to calculate the P-value for this sample. P-value = (Report answer as a decimal accurate to 4 decimal places.) This P-value (and test statistic) leads to a decision to... reject the null accept the null fail to reject the null reject the alternative As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program. There is not sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program. V ' The sample data support the assertion that there is a different proportion of only children in the Question Help: Message instructor G&T program. There is not sufficient sample evidence to support the assertion that there is a different . Question 12 E 0/1 Pt '0 3 Z 99 proportion of only children in the G&T program. Test the claim that the proportion of men who own cats is significantly different than 15% at the 0.2 significance level. ' > The null and alternative hypothesis would be: Question Help: 8 Message instructor H0 :11 0.15 H0337 0,15 H041. How. Hugo 0.15 How. H1:p70.15 ng b Question 11 80/1 pt '0 3 399 Given p = 0.2857 and N = 35 for the high Income group, The test is: Test the claim that the proportion of children in the high income group that drew the nickel too right-tailed left-tai led two-tailed large is smaller than 50%. Test at the 0.05 significance level. ' a) Identify the correct alternative hypothesis: ,7 p _ 50 In a random sample of 115 men, 63 men owned cats. 11 > .50 The P-value of this sample is (to 4 decimals). u .50 P

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

A Tour Through Graph Theory

Authors: Karin R Saoub

1st Edition

1138197815, 9781138197817

More Books

Students also viewed these Mathematics questions

Question

What does this look like?

Answered: 1 week ago