The saturation temperature of refrigerant-12, Ts, corresponding to a pressure of 0.4 MPa is 8.15C. The specific internal energies of the saturated liquid and the saturated vapor are, respectively, u, = 43.35 kJ/kg and ug = 173.69 kJ/kg. Deduce the state of the refrigerant for the following cases, locate it on P-V and T-v curves and explain: (1) P = 0.4 MPa, u = 175 kJ/kg (3) P = 0.4 MPa, T = 10C (5) T= 8.15C (281.3 K), P = 0.42 MPa (2) P = 0.4 MPa, u = 40 kJ/kg (4) P = 0.4 MPa, u = 100 kJ/kg (6) P = 0.4 MPa, T = -4C