The scores on a test are normally distributed with a mean of 140 and a standard deviation of 28. What is the score that is 3 standard deviations below the mean? <:> A score of is 3 standard deviations below the mean. The scores on a test are normally distributed with a mean of 30 and a standard deviation of 6. Find the score that is onehalf a standard deviation below the mean. A score of D is one-half a standard deviation below the mean. - 1 The scores on a test are normally distributed with a mean of 100 and a standard deviation of 10. Find the score that is 35 standard deviations above the mean. <:> 1 A score of is 35 standard deviations above the mean. The figure illustrates a normal 99.7% distribution for the prices paid for a 95% particular model of a new car. The mean is $12,000 and the standard deviation is $500. Number of Car Buyers Use the 68-95-99.7 Rule to find the percentage of buyers who paid between $10,500 and $12,000. In 10,500 11,000 11,500 12,000 12,500 13,000 13,500 Price of a Model of a New Car What percentage of buyers paid between $10,500 and $12,000?Not everyone pays the same price for 99.7% the same model of a car. The figure 95% illustrates a normal distribution for the +68%- prices paid for a particular model of a new car. The mean is $20,000 and the Number of Car Buyers standard deviation is $2000. Use the 68-95-99.7 Rule to find the percentage of buyers who paid less than $18,000. 14 16 18 20 22 24 26 Price of a Model of a New Car (Thousands) The percentage of buyers who paid less than $18,000 is %.Not everyone pays the same price for 99.7% the same model of a car. The figure 95% illustrates a normal distribution for the +68%- prices paid for a particular model of a new car. The mean is $24,000 and the Number of Car Buyers standard deviation is $1000. Use the 68-95-99.7 Rule to find what percentage of buyers paid between $21,000 and $27,000. 21 22 23: 24 25 26 27 Price of a Model of a New Car (Thousands) The percentage of buyers who paid between $21,000 and $27,000 is %.Scores on the GRE (Graduate Record Examination) are normally distributed with a mean of 592 and a standard deviation of 117. Use the 68-95-99] Rule to nd the percentage of people taking the test who score between 358 and 826. The percentage of people taking the test who score between 358 and 826 is %. Scores on the GRE (Graduate Record Examination) are normally distributed with a mean of 554 and a standard deviation of 1 15. Use the 68-95-99] Rule to nd the percentage of people taking the test who score above 899. The percentage of people taking the test who score above 899 is %. A set of data items is normally distributed with a mean of 180 and a standard deviation of 24. Convert 132 to a zscore. (I> Z132=|:| (Type an integer or a decimal. Do not round until the nal answer. Then round to the nearest hundredth as needed.) A set of data items is normally distributed with a mean of 60 and a standard deviation of 9. Convert 54 to a z-score. <:> 254g (Do not round until the final answer. Then round to the nearest hundredth as needed.) Scores on the GRE (Graduate Record Examination) are normally distributed with a mean of 538 and a standard deviation of 122. Use the 68-95-99] Rule to nd the percentage of people taking the test who score below 416. The percentage of people taking the test who score below 416 is %. A set of data items is normally distributed with a mean of 200 and a standard deviation of 40. Find the data item in this distribution that corresponds to the given z-score. z=7 <:> The data item that corresponds to z = 7 is E. (Type an integer or a decimal.) Scores on a dental anxiety scale range from 0 (no anxiety) to 20 (extreme anxiety). The scores are normally distributed with a mean of 11 and a standard deviation of 4. Find the z-score for the given score on this dental anxiety scale. 20 220 = (Type an integer or a decimal.) Scores on a dental anxiety scale range from 0 (no anxiety) to 20 (extreme anxiety). The scores are normally distributed with a mean of 11 and a standard deviation of 4. Find the z-score for the given score on this dental anxiety scale. 13 213 = (Type an integer or a decimal.) The data in the accompanying bar graph are from a random sample of 881 adults. The graph shows four proposals to Proposals to Reduce Gun Violence reduce gun violence in a country and the percentage of surveyed adults who favored each of these proposals. Complete parts (a) and (b) below. 80- 62% 58% 60- 57% 55% Percentage of Adults Favoring the Proposal 40- 20- 0- Required Ban on Ban on Restrict amount or gun registration high-capacity assault type of ammunition magazines weapons purchases .. a. Find the margin of error for this survey. The margin of error is + %. (Do not round until the final answer. Then round to the nearest tenth as needed.)A set of data items is normally distributed with a mean of 300 and a standard deviation of 30. Find the data item in this distribution that corresponds to the given z-score. z=-6 <:> The data item that corresponds to z = - 6 is E. (Type an integer or a decimal.) Using a random sample of 2147 TV households, Acme Media Statistics found that 41% watched the final episode of "I Can't Take it Anymore!" a. Find the margin of error in this percent. b. Write a statement about the percentage of TV households in the population who tuned into the nal episode of "I Can't Take it Anymore!" a. The margin of error is t %. (Do not round until the final answer. Then round to the nearest hundredth as needed.)