The semicircular region bounded by the curve a: = 1/ 4 y2 and the y-axis is revolved about the line a: = 3. The integral that represents its volume is V=fftyldy where wt) 1- See Example 4 page 234 for a similar problem. The region R is in the first quadrant and bounded by the x-axis, the y axis, and y = 3 + 2a - x2. Find the volume of the solid that results when R is revolving about a = 0.Find the area of the region enclosed between 3; = 2 sin(:::) and y = 4 606(3) from a: = O to a: = 1a: Hint: Notice that this region consists of two parts. Find the volume of the solid of revolution obtained by revolving the plane region R bounded by y : 13, the yaxis, and the line y : 6 about the m-axis. See Example 2 page 233 for a similar problem..._oe careful: the axis of rotation is different