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The semicircular region bounded by the curve x = V16 - y and the y-axis is revolved about the line x = -4. The integral

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The semicircular region bounded by the curve x = V16 - y and the y-axis is revolved about the line x = -4. The integral that represents its volume is V fly) dy a where a = , b , and f(y) = See Example 4 page 284 for a similar problem.Let the base of a solid be the first quadrant plane region bounded by m = 1 312/16, the m-axis, and the y-axis. Suppose that cross sections perpendicular to the y -axis are squares. Find the volume of the solid See Example 5 page 285 for a similar problem. Let the base of a solid be the first quadrant plane region bounded by y : 1 x2/25, the x-axis, and the yaxis. Suppose that cross sections perpendicular to the m-axis are equilateral triangles sitting on the base. Find the volume of the solid. See Example 6 page 286 for a similar problem. 1;4 The region bounded by y = a: : the m-axis, :r: = 1. and a: = 4 is revolved about The yaxis. Find the volume of the resulting solid. See Example 1 page 289 for a similar problem. The region bounded by the line y : (ix/81 the :c-axis, and a: : 8 is revolved about the x-axis' thereby generating a Gone. To find its volume by the shell method: you would evaluate the integral 5 V: f 21Tyfiy)dy where b 2 fl?!) = The volume is V = See Example 2 page 290 for a similar problem. Find the volume of the solid generated by revolving the region in the first quadrant that is above the parabola y = 5x and below the parabola y = 54 - a about the y-axis. See Example 3 page 290 for a similar

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