The simple air Brayton cycle shown below produces power (Wet) as well as 10 tons of refrigeration (ref = 10 tons) with an absorption chiller (COP = 0.7) driven by the waste heat from the turbine. In order to provide the required heat transfer to the chiller the turbine exhaust temperature is T4 = 160C, and the turbine exhaust air leaving the chiller is Ts = 120C. Air enters the compressor at T = 27C and P = 100 kPa, and exhausts the turbine at P4 = 100 kPa. The compressor compresses the air to a pressure of P = 1.5 MPa. The compressor (n.) and turbine (nt) isentropic efficiencies are nc = t = 90%. Treating the Brayton cycle as cold-air standard with specific heats evaluated at 300 K, what is the CHP system total efficiency total, defined as 1 total (Net Power Out) + (Cooling Rate)_ Wnet + Oref Heat Input Rate 2in 0 P = 1.5 MPa 2 Compressor Compressor Isentropic Efficiency: nc = 90% (1) T = 27C P = 100 kPa Combustor 3 Turbine T4 = 160C, P = 100 kPa 4 Ts=120C (5) W net Turbine Isentropic Efficiency: nt = 90% Absorption Chiller COP = 0.7 Q = 10 tons Refrigeration Load