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The solution of the differential equation $$ y^{prime prime}+25 y=-60 cos (5 x)-40 sin (5 x) $$ subject to the initial conditions $y(0)=0$ and

 

The solution of the differential equation $$ y^{\prime \prime}+25 y=-60 \cos (5 x)-40 \sin (5 x) $$ subject to the initial conditions $y(0)=0$ and $y^{\prime}(0)=4$ is $$ y(x)= $$

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