The solutions (x,y) of the equation x + 16y2 = 16 form an ellipse as pictured below. Consider the point P as pictured, with x-coordinate 2. (a) The ellipse is not given by a single function as it fails the vertical line test. It is given by two function. The points P and Q shown are in the upper part which can be described as y=f(x) were f(x)= (b) Let h be a small non-zero number and form the point Q with x-coordinate 2+h, as pictured. Then, the y-coordinate of Q is given by (c) Let h be a small non-zero number and form the point Q with x-coordinate 2+h, as pictured. The slope of the secant line through PQ, denoted s(h), is given by the formula (d) Rationalize the numerator of your formula in (c) and simplify to rewrite the expression so that it looks like f(h)/g(h), subject to these two conditions: (1) the numerator f(h) defines a line of slope -1, (2) the function f(h)/g(h) is defined for h=0. (When you b finished your simplification, neither the numerator nor the denominator should become zero when h=0.) When you do this f(h)= g(h)- (e) The slope of the tangent line to the ellipse at the point P is lims (h) 714