The standard enthalpy change for the following reaction is

436.4k(J)/(m)ol

:\

H_(2)(g)->H(g)+H(g)

\

\\\\Delta t=436.4k(J)/(m)ol

\ Calculate the standard enthalpy of formation of atomic hydrogen

(H)

.\ Ans.

218.2k(J)/(m)ol

\

\\\\Delta H=\\\\Delta n=n_(prod )-n_(reactants )

12. The standard enthalpy change for the following reaction is 436.4kJ/mol : H2(g)H(g)+H(g) 1=436.4kJ/mol Calculate the standard enthalpy of formation of atomic hydrogen (H). Ans. 218.2kJ/mol H=n=nprodnreactants