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The standard equation of a circle with center (-4, 3) and radius 7 isa (x-4) + (x+3) = 7b (x + 4) + (y -
The standard equation of a circle with center (-4, 3) and radius 7 isa (x-4)² + (x+3)² = 7b (x + 4) + (y - 3) = 7c (x-4)² + (x+3)² =d (x+4)² + (y-3)² = 49
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