The standard reaction enthalpy for the hydrogenation of propene is ${}_T{H}_{2980}=-124$

$k\frac{J}{m}ol.$ While, standard reaction enthal py for the combustion of propane is ${}_r{H}_{2980}=$

$-2220k\frac{J}{m}ol.$ Meanwhile, water standard enthalpy of formation is ${}_f{H}_{2980}=-286$

$k\frac{J}{m}ol.$ Calculate the standard enthalpy of combustion of propene.

$(12$ Marks$)$