Question
The steam reforming reaction can be described by the following two reactions: CH 4 +H 2 O ? CO+3H 2 CH 4 +2H 2 O
CH4 +H2O ? CO+3H2
CH4 +2H2O ? CO2 +4H2
Assume that both these reactions achieve equilibrium at 600 K. The equilibrium constants at this temperature for the two reactions are 0.41 and 1.09 respectively. Calculate the equilibrium composition if the starting composition is 5 moles of steam and 1 mole of methane at a pressure of 2 atm.
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Intermediate Accounting
Authors: Donald E. Kieso, Jerry J. Weygandt, And Terry D. Warfield
13th Edition
9780470374948, 470423684, 470374942, 978-0470423684
