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The table below shows the number of one companv's stores located in each of 50 regions. Complete parts (a) through (c) below. 63 22 78
The table below shows the number of one companv's stores located in each of 50 regions. Complete parts (a) through (c) below. 63 22 78 54 567 82 68 17 12 306 [:11 125 25 28 191 125 67 55 77 82 34 96 1 15 1 60 84 50 99 30 31 40 36 159 42 341 136 10 201 59 68 234 23 68 22 86 407 43 18 143 1 1 1 36 1 05 <:> a. Compute the mean, variance, and standard deviation for this population. The population mean is p = E. (Type an integer or a decimal. Round to one decimal place as needed.) . . . 2 The population variance Is 0' = D. (Round to the nearest integer as needed.) NOTE: To calculate the variance, do not round standard deviation vaiue. This is to avoid the rounding error. The population standard deviation is U = D. (Type an integer or a decimal. Round to one decimal place as needed.) b. What percentage of the 50 regions have stores within 1: 1, i 2, or :I: 3 standard deviations of the mean? The percentage within :1 standard deviation of the mean is El%. (Type an integer or a decimal. Do not round.) The percentage within :l: 2 standard deviations of the mean is |:|%. (Type an integer or a decimal. Do not round.) The percentage within :I: 3 standard deviations of the mean is |:|%. (Type an integer or a decimal. Do not round.) 0. Compare your ndings in part (b) with what would be expected on the basis of the empirical rule. Are you surprised at the results in part (b)? O A. No, because the percentage values are close to those predicted by the empirical rule. 0 B. Yes, because all the data are within :I: 2 standard deviations of the mean. 0 6. Yes, because a much higher percentage of regions are within :1: 1 standard deviation of the mean than would be expected on the basis of the empirical rule. 0 D. Yes, because a much lower percentage of regions are within i 1 standard deviation of the mean than would be expected on the basis of the empirical rule
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