The table shows the masses of fish caught in a fishing competition. Calculate the 80th percentile Mass (kg) Frequency 4-6 3 6 8 8-10 9 10-12 6 12-14 -N 14-16 A ll kg C 13 kg B 9kg D None of these A OB O c OD 1 po A set of data is summarized: Q1 = 5.6 kg Q3 - 9.2 kg Median = 6.6 kg Lower extreme = 1.I kg Upper extreme = 14.8 kg Which is a correct statement? A 1.1 kg is the only outlier. C 1.1 kg and 14.8 kg are both outliers. B 14.8 kg is the only outlier. D There is no outlier. OA B O c ODWhich is a correct statement comparing these data sets? Data Set A Data Set B Mean 25.9 cm 28.2 cm Standard Deviation 3.4 cm 2.8 cm A On average, the data are greater in Set A and are more spread out in Set A. B On average, the data are greater in Set B but are more spread out in Set A. C On average, the data are greater in Set B and are more spread out in Set B. D On average, the data are greater in Set A but are more spread out in Set B. OA O B O c OD 1 poi Which is a correct statement regarding a weighted mean? A The weighted mean is less affected by outliers than the median. B Multiply the weighting by the corresponding data value, then find the sum of the products. C A weighted mean is always different from the actual mean. D A weighted mean accounts for the relative importance of each value in the average. O A O B O c ODWhat does a z-score of -2.0 represent? A The mean is 2 standard deviations less than the measurement. B The measurement is 2 standard deviations less than the mean. C There is an error in the measurement. D The variance cannot be calculated because the z-score is negative. OA OB OC OD 1 point The table shows the waiting time for customers while having winter tires installed on their cars. What is the standard deviation? Mass (kg) Frequency 30-35 10 35-40 16 40-45 21 45-50 17 50-55 19 55-60 60-65 A 45 minutes C 64 minutes 8 minutes D None of these OA O O c ODThe mean of a data set is 12.5 cm, and the variance is 4.0 em. What is the z-score of 9.5? A 0.75 C 15 B -0.75 D -1.5 QA OB OC OD 1 point Ed had a mark of 75 out of 80 on a test, which had a mean mark of 60 and a standard deviation of 7.5. Sam had a mark of 78 out of 90 on a test, which had a mean mark of 66 and a standard deviation of 6.0. Statistically, who had the better mark compared to the rest of his class? A Ed had a better mark. H Sam had a better mark C You cannot tell who did better with the given information. D The two scores are statistically the same. A OB OC ODIf a value represents the 95th percentile, this means that A 95% of all values are greater than the value. B this value will occur 95% of the time. C 95% of all values are less than or equal to the value. D there is a 95% chance that this value is correct. O A O B C OD 1 poin Which list of measures of central tendency represents the ranking from most to least affected by outliers? A mean, median, mode C median, mean, mode B mean, mode, median D mode, mean, median O OB O c OD