Question
The term, kT/q , appears often in semiconductor devicemodels. a) Find the value of kT /q at a room temperature of 80F. Some useful information:
The term, kT/q , appears often in semiconductor devicemodels.
a) Find the value of kT /q at a ‘room temperature’ of 80F.
Some useful information: k is known as Boltzmann’s constant andis equal to k = 1.381×10^?23 Joule/ Kelvin = 8.617 ×10^?5 eV/Kelvin . To compute kT /q we divide kT by q = e , hence we use thesecond form of the Boltzmann constant, k = 8.617 ×10^?5 eV /Kelvin. Note that q = e cancels the e in the units of eV . To cancel theunits of Kelvin , we need to convert temperature into units ofKelvin. To find the temperature in Kelvin from Celsius, add 273.15to the temperature in Celsius.
b) Find the value of kT/ q at the boiling point of water.
Step by Step Solution
3.56 Rating (160 Votes )
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get StartedRecommended Textbook for
Physics
Authors: John D. Cutnell, Kenneth W. Johnson
9th edition
470879564, 1118424840, 470879521, 9780470879566, 9781118424841, 978-0470879528
Students also viewed these Electrical Engineering questions
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
View Answer in SolutionInn App