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The transverse displacement of an harmonic wave on a stretched rope is y = 0.03 cos(3.2 x - 6.4 t), where x and y are
The transverse displacement of an harmonic wave on a stretched rope is y = 0.03 cos(3.2 x - 6.4 t), where x and y are in meters and t is in seconds.
1) What is the amplitude of this wave?
A =
2) What is the wavelength of this wave?
l =
3) What is the speed with which this wave travels?
|v| =
4) In what direction is this wave propagating?
+x
-x
+y
-y
+z
-z
none of the above
5) What is the frequency (NOT the angular frequency) of this wave?
f =
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y 003 cos 32 x 614t 003603 1646 32x 1 Amplitude of this ware is A 003 m ...Get Instant Access to Expert-Tailored Solutions
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