The uncertainty in position is $1\mathrm{.}0$ nm for a particle of mass $2\mathrm{.}0$x$10-27$ kg$.$ Calculate

the minimum uncertainty in the particles momentum. $($Apply Heisenberg$$s

uncertainty principle $(\backslash$Delta x $\backslash$Delta p $>=/2).$Use:

$=\frac{h}{2}=\frac{6\mathrm{.}626{10}^{-34}Js}{2}$

Mass of an electron $=9\mathrm{.}109{10}^{-31}kg$

Mass of a proton $=1\mathrm{.}67{10}^{-27}kg$

Speed of light $=3{10}^8\frac{m}{s}$