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The value of Fo at 121C (250F) for a 99.999% inactivation of the spores of the Clostridium botulinum strain is 1.2 min. What is the
The value of Fo at 121C (250F) for a 99.999% inactivation of the spores of the Clostridium botulinum strain is 1.2 min. What is the value of Do for this organism? What is the probability of microbial inactivation expressed as number of containers with the presence of at least one spore?
2. Take 12 to be the minimum sterilization value (n) for inactivation of spores of the microorganism PA3679. Calculate the Fo considering the value of Do reported for the inactivation of the spores of this microorganism
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