The value of the limit n 62 lim 3+ 1= 1 n n is equal to the area below the graph of a function f(a)
The value of the limit n 62 lim 3+ 1= 1 n n is equal to the area below the graph of a function f(a) on an interval [A, B]. Find f, A, and B. (Do not evaluate the limit.) f (2 ) = A = 0 (use A = 0) B =
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