The vapor pressure in a tank will be measured with a mercury U$-$manometer. There is water at a height of $48$mm in the branch of the U$-$pipe connected to the tank due to the condensation of some of the steam. A pressure $35$mmHg greater than atmospheric pressure occurs on the right side of the U$-$manometer. Since the atmospheric pressure is $76\mathrm{.}51$cmHg$,$ find the pressure of the steam in the tank in pascals $($Pa$).$ If the effect of condensed water is neglected, determine the error in $\%.(\backslash$rho mercury$=13600$kg$/$m$3,\backslash$rho water$=1000$kg$/$m$3)$