The vapor pressure of propane is given by the Antoine Equation $lo{g}_{10}{p}^{\text{s}\text{a}\text{t}}=4\mathrm{.}53678-\frac{1149\mathrm{.}36}{T+24\mathrm{.}906}$

psat is in bar and $T$ in $K.$ Convert the equation to one relating $p^{\text{s}\text{a}\text{t}}($psia$)$ to $T(F).$