The vapor pressures of benzene (1) and toluene (2) can be evaluated by the following Antoine equations In P1^sat = 13.8594 - 2773.78/220.07+ T ln P2^sat = 14.0098 - 3103.01/ 219.79 + T Where, T is in C and P1^sat is in kPa. Assuming that the solutions formed by these are ideal, calculate x, y and fraction of the volume (V/F), when T = 100C, P = 1 bar and overall mole fraction of benzene (z) =0.4. x's and y's are liquid and vapor mole fraction respectively.