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The velocity distribution in a horizontal, rectangular, open channel is expressed by u = umax(y/d)n, where u is the velocity at a distance y meter

The velocity distribution in a horizontal, rectangular, open channel is expressed by u = umax(y/d)n, where u is the velocity at a distance y meter above the floor of the channel. If the depth d of flow is 1.8 m, umax = 7.2 m/s, and n = 1/7, what is the discharge in m3/s per meter of width of channel? What is the mean velocity

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