The velocity v(t) of a sprinter on a straight track is shown in the graph below. UnT 3 v (t) 1 -1 -3 -5 N 4 6 10 t Determine the evaluator of each definite integral. So v(1) dt = 20 (4 v(1) dt = .5 ST v(t) dt = -10 So v(1) dt = 10.51 Submit Answer Incorrect. Tries 4/8 Previous Tries If s'(t) = v(t), then s(t) is the position of the runner at time t. Let s(0) = -2, determine the following values. s(4) = s(5) = s(7) = s(9) = Submit Answer Tries 0/8