Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

The Venturi tube shown in the figure below may be used as a fluid flowmeter. Suppose the device is used at a service station to

image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed
image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed
The Venturi tube shown in the figure below may be used as a fluid flowmeter. Suppose the device is used at a service station to measure the flow rate of gasoline (p = 7.00 x 10- kg/m) through a hose having an outlet radius of 1.27 cm. The difference in pressure is measured to be P, - P, = 1.40 kPa and the radius of the inlet tube to the meter is 2.54 cm. P 1 (a) Find the speed of the gasoline as it leaves the hose. m/s (b) Find the fluid flow rate in cubic meters per second. m3/sPractice Another X The Venturi tube shown in the figure below may be used as a fluid flowmeter. Suppose the device is used at a service station to measure the flow rate of gasoline (p = 7.00 x 102 kg/m) through a hose having an outlet radius of 1.16 cm. The difference in pressure is measured to be P, - P, = 1.10 kPa and the radius of the inlet tube to the meter is 2.32 cm. P1 (a) Find the speed of the gasoline as it leaves the hose. 3 X Your response differs from the correct answer by more than 10%. Double check your calculations. m/s (b) Find the fluid flow rate in cubic meters per second. 6 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. m /sSolution or Explanation : Note: We are displaying rounded intermediate values for practical purposes. However, the calculations are made using the unrounded values. (a) P2 VI V/2 A2 A : Since the tube is horizontal, y, = y, and the gravity terms in Bernoulli's equation cancel, leaving P 1 + = pv1= = P2 + = pv2 2 - - -- 2 2 . 2(P - P2) 2(1.10 x 10* Pa) P 7.00 x 102 kg/m3 land (,2 - v 2 = 3.14 m2/s2. [1] : From the continuity equation, A V, = A,v,, we find V 2 = A1)v1 = -1 = (2.32 cm 2 A , V1 1.16 cmor V, = 4V. [2] Substituting Equation [2] into [1] yields 15v 2 = 3.14 m /s , and v, = 0.458 m/s. Then, Equation [2] gives v, = 4(0.458 m/s) = 1.83 m/s. (b) The volume flow rate is 1 = Azz = (7r,")v, = (1.16 x 10-2 m)2(1.83 m/s) = 7.74 x 10-4 m3/s

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Applied Physics

Authors: Dale Ewen, Neill Schurter, Erik Gundersen

11th Edition

9780134159386

More Books

Students also viewed these Physics questions

Question

What reward will you give yourself when you achieve this?

Answered: 1 week ago