The vertical bar $AB$ has a mass of $100+abkg$ with center of mass $G$ midway between the ends. The bar

is elevated from rest at $=0$ by means of the parallel links of negligible mass, with a constant couple

$M=5+bkNm$ applied to the lower link at $C.$ Determine the angular acceleration $$ of the links as a function

of $$ and find the force $B$ in the link DB at the instant $=(30+a).($ab is the las two digits of Student

ID$.$ For example if Student ID is $2000114526$ then $a=5,b=7$ and $ab=57.$ Hence Mass$=157kg$ and $M=12$

$kNm,=35)$ please solve free body diagram