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The vertical bar A B has a mass of 1 0 0 + a b ( a b = 1 2 ) k g with

The vertical bar AB has a mass of 100+ab(ab=12)kg with center of mass G midway between the ends. The bar
is elevated from rest at =0 by means of the parallel links of negligible mass, with a constant couple
M=5+bkm(b=2) applied to the lower link at C. Determine the angular acceleration of the links as a function
of and find the force B in the link DB at the instant =(30+a)( a=1)(ab is the las two digits of Student
ID. For example if Student ID is 2000114526 then a=2b=6 and ab=26. Hence Mass =126kg and M=11
kNm,=32
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