The vertical bar $AB$ has a mass of $100+ab(ab=12)kg$ with center of mass $G$ midway between the ends. The bar

is elevated from rest at $=0$ by means of the parallel links of negligible mass, with a constant couple

$M=5+bkm($b$=2)$ applied to the lower link at $C.$ Determine the angular acceleration $$ of the links as a function

of $$ and find the force $B$ in the link DB at the instant $=(30+a)($ a$=1)($ab is the las two digits of Student

ID$.$ For example if Student ID is $2000114526$ then $a=2b=6$ and $ab=26.$ Hence Mass $=126kg$ and $M=11$

$kNm,=32$