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The vertical position y (in feet) of a rock t seconds after it was dropped from a cliff is given by the formula y=-16t+14t+200.

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The vertical position y (in feet) of a rock t seconds after it was dropped from a cliff is given by the formula y=-16t+14t+200. The base of the cliff corresponds to y=0. How many seconds will it take for the rock to hit the ground at the base of the cliff?

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