The W= 4 kN/m uniformly distributed loaded composite steel beam is shown in Figure (a). The steel composite section consists of two steel plates, each with dimensions of 209 x 30mm and a universal beam section Section 4 (See Table 1) are bolted together to form the composite section as shown in Figure (b). The 16 mm diameter bolts are spaced longitudinally every 150 mm. The sectional properties are given in Figure (c) and Table 1. The modulus of elasticity for steel is 200 GPa. a a 10 m. w kN/m Figure (a) Simply supported beam Steel plate UB Section Steel plate (b) Section a-a (dimensions not to scale) Figure (b) Section a-a & (c) UB section -b- Yo (c) UB Section Table 1. Sectional properties UB Section A d Section X y 1 610UB125 2 610UB113 3 610UB101 4 530UB92.4 5 530UB82 If tu mm mm mm mm mm 16000 612 229 14500 607 228 13000 602 228 11800 533 209 10500 528 209 br lyo (x100 mm) (x108 mm) 19.6 11.9 17.3 11.2 986 39.3 875 34.3 14.8 10.6 761 29.3 15.6 10.2 554 23.8 13.2 9.6 477 20.1 Table 1. Sectional properties UB Section A d br Section X y tf tu lyo mm 1 610UB125 2 610UB113 3 610UB101 4 530UB92.4 5 530UB82 mm 16000 612 229 14500 607 228 13000 602 228 11800 533 209 10500 528 209 mm mm mm (x108 mm) (x100 mm) 19.6 11.9 17.3 11.2 986 39.3 875 34.3 14.8 10.6 761 15.6 10.2 554 13.2 9.6 477 29.3 23.8 20.1 a) Calculate the maximum bending moment and shear force; Mmax = kNm Vmax= KN b) Determine the location of the centroid with respect to the point P; y = mm c) Determine the moment of inertia I,, with respect to the centroidal axes. xx = x106 mm