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Theoretical Value of G = 9.81 Mass 1: 0.26 kg Mass 2: 0.2515 kg Setup 2 Trial Acceleration Mass difference Total Mass m/s (kg) (kg)
Theoretical Value of G = 9.81
Mass 1: 0.26 kg Mass 2: 0.2515 kg Setup 2 Trial Acceleration Mass difference Total Mass m/s (kg) (kg) 0.0474 m/s2 0.0085 kg 0.5115 kg N 0.0328 m/s 0.0085 kg 0.5115 kg 3 0.0388 m/s 0.0085 kg 0.5115 kg Computation for dave Given: a1 = 0.0474 m/s2 a2 = 0.0328 m/s2 a3 = 0.0388 m/s Required: Cave = ? Average Equation: Cave =- Ea Solution: Clave = 0.0474 m/$2 + 0.0328 m/s2 + 0.0388 m/s2 Answer: Clave = 0.0397 m/s2 Computation for g Given: a = 0.0397 m/s m1 = 0.26 kg m2 = 0.2515 kg Required: g =? Acceleration due to Equation: gravity (g) a(m, +m ) g = - m -m2 Solution: g = - 0.0397 m/s2 (0.26 kg+0.2515 kg) 0.26 kg - 0.2515 kg Answer: g = 2.0247 m/s2Mass 1: 0.3015 kg setup 3 Mass 2: 0.21 kg Trial Acceleration Mass difference Total Mass kg) (kg) 0.1084 m/s 0.0915 kg 0.5115 kg 2 0.0168 m/s2 0.0915 kg 0.5115 kg 3 0.0161 m/s2 0.0915 kg 0.5115 kg Average Computation for dave Given: a1 = 0.1084 m/s a2 = 0.0168 m/s2 a3 = 0.0161 m/s2 Required: Cave = ? Equation: a ave = 3 Solution: a ave = - 0.1084 m/$2 + 0.0168 m/s2 + 0.0161 m/s2 Answer: dave = 0.0471 m/s2 Acceleration due to Computation for g gravity (8) Given: a = 0.0471 m/s m1 = 0.3015 kg m2 = 0.21 kg Required: g =? Equation: a(m, +m , ) g = m -mz Solution: g = - 0.0471 m/s (0.3015 kg + 0.21 kg) 0.3015 kg - 0.21 kg Answer: g = 0.2633 m/s25. Is the recorded acceleration due to gravity value for the pulley system in each setup accurate to the theoretical value of g? Explain why or why not.Table 1. Acceleration in Varying Mass Difference Mass 1: 0.31 kg Setup I Mass 2: 0.2015 kg Trial Acceleration Mass difference Total Mass kg (kg) 0.1359 m/s 0.1085 kg 0.5115 kg 2 0.1970 m/s2 0.1085 kg 0.5115 kg W 0.1258 m/s2 0.1085 kg 0.5115 kg Computation for dave Given: a1 = 0.1359 m/s2 a2 = 0.1970 m/s2 a3 = 0.1258 m/s2 Required: a ave = ? Average Equation: adave =- Ea 3 Solution: dave = 0.1359 m/$2 + 0.1970 m/s2 + 0.1258 m/s2 3 Answer: Cave = 0.1529 m/s2 Computation for g Given: a = 0.1529 m/s2 m, = 0.31 kg m2 = 0.2015 kg Required: g = ? Acceleration due to Equation: gravity (g) a(m +m) g = m -m2 Solution: g = 0.1529 m/s2 (0.31 kg+0.2015 kg) 0.31 kg - 0.2015 kg Answer: g = 0.7208 m/s2Step by Step Solution
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