Question
There are 88 keys on a standard piano. Each key produces a music note that is at a different frequency (a different musical pitch). For
There are 88 keys on a standard piano. Each key produces a music note that is at a different frequency (a different musical pitch). For example the A4 note on a piano is key 49 and has a frequency of 440.0 Hz. You can convert any piano key into its corresponding frequency using the following formula: Where n is the piano note number (between 1 and 88) and f(n) gives the frequency in Hertz. Note that 2 is raised to the power of that fraction. You are given a Helper file for this assignment called StdAudio.java and a starter BlueJ project. You should add your solution to this existing BlueJ project. The helper file allows you to play a musical note (provided you supply a frequency (double), duration (in seconds) (double) ) and volume (as a percentage) (double). For example to play an A4 note for 0.7 seconds at half volume you do as follows: StdAudio.play(440.0, 0.7, 0.5); //or similarly: double a4 = 440.0; StdAudio.play(a4, 0.7, 0.5); For Problem 1 you will create a program that plays a musical note (a piano key between 1 and 88 of your predetermined choosing) and asks the user to guess what the note is. The user will be asked to input a number between 1 and 88 representing their guess as to which piano key matches the sound they heard. Your program will then play their note so they can hear what they have input. You should output the user guessed piano key number and the corresponding frequency and the actual piano key number and its corresponding frequency indicating by how many keys the user was incorrect - or a congratulatory message if they got it correct
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