There are four radio stations in Midland. The stations have different formats (hard rock, classical, country and western, and easy listening), but each is concerned with the number of minutes of music played per hour. From a sample of 10 hours from each station, the following sample means were offered: X1 = 52.07 X2 = 44.66 X3 = 47.21 X4 = 50.34 55 total = 558.000 a. Determine SST. (Round the final answer to 3 decimal places.) SST = 32.521 6 b. Determine SSE. (Round the final answer to 3 decimal places.) SSE = 32.172 0 c. Complete an ANOVA table. (Round the SS, MS, and F-values to 3 decimal places.) ANOVA Source of DE MS Variation Treat 0. 348 x 0. 348 0 3. 022 x x Error 32.172 16. 086 Total 32.521 The following hypotheses are given. Ho: H1 = H2 = 13 = H4 Hy: The means are not all equal. d. State the decision rule for 0.10 significance level. (Round the final answer to 2 decimal places.) Reject Ho if F> 0.896 At the 0.10 significance level, is there a difference in the treatment means? There is a difference in the treatment means. e. Develop a 90% confidence interval for the difference in the mean amount of music time between station 1 and station 4. (Negative answer should be indicated by a minus sign. Round the final answers to 3 decimal places.) The 90% confidence interval is between 44.696 @ and |52.444 @ Is there a difference in the mean amount of music time between station 1 and station 4? Use the 0.10 significance level. There is no difference