There are three jugs with capacities of $12$ gallons, $7$ gallons, and $5$ gallons. The $12-$gallon jug is full of water, and the other two jugs are empty. None of the jugs has any markings on them. There are no other additional measuring devices available. Find the fewest number of pourings required to divide water in the $12-$gallon jug into two equal parts of $6$ gallons each $($leaving the smallest jug empty$).$