There is a two-component liquid-vapour system containing components A and B. The relative volatility of component A (QAB or a by convention) is 3.00. At equilibrium, the temperature T and the molar fraction of composition A in the hiquid phase has the following relationship: 80.0-T e 20.0 -0.200 (Unit: T - C, and x- molar fraction) 0.800 Note that a, the relative volatility of component A. provides a link to the relationship between y And x as follows, so that you can calculate y from x: ax XA 1- x + ax We are given a total vapour feed of 240.0 kmol, with 41% component A and at a temperature of 200C. This vapour is now allowed to cool down until 40.0 kmol is condensed to liquid. What is the temperature (the first temperature T) at which we have exactly 200.0 kmol of vapour. At this point, the cooled liquid is separated out and the remaining vapour is again cooled down until its half becomes liquid. What should be the second temperature T2? If this process is to be repeated one more time, i.e., the remaining vapor is further cooled down until its half becomes liquid. What is the third temperature T3, required? What is the total amount of vapour and liquid obtained and what are their compositions? You are required to carry out the calculation analytically