Therefore, the work done is as follows. 211' W / (t t cos(t) + 2 sin(t)) dt

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Therefore, the work done is as follows. 211' W / (t t cos(t) + 2 sin(t)) dt 0 E9 - (t sin(t) + cos(t)) - 2 m E"

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Therefore, the work done is as follows. 211' W / (t t cos(t) + 2 sin(t)) dt

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